本文章来为各位介绍一篇关于php计算两个坐标(经度，纬度)之间距离的方法，希望这篇文章能够帮助到各位同学的哦。

例子一

function distance($lat1, $lng1, $lat2, $lng2, $miles = true)

{

$pi80 = M_PI / 180;

$lat1 *= $pi80;

$lng1 *= $pi80;

$lat2 *= $pi80;

$lng2 *= $pi80;

$r = 6372.797;

$dlat = $lat2 - $lat1;

$dlng = $lng2 - $lng1;

$a = sin($dlat/2)*sin($dlat/2) cos($lat1)*cos($lat2)*sin($dlng/2)*sin($dlng/2);

$c = 2 * atan2(sqrt($a), sqrt(1 - $a));

$km = $r * $c;

return ($miles ? ($km * 0.621371192) : $km);

}

例子二

/**

* 计算两个坐标之间的距离(米)

* @param float $fP1Lat 起点(纬度)

* @param float $fP1Lon 起点(经度)

* @param float $fP2Lat 终点(纬度)

* @param float $fP2Lon 终点(经度)

* @return int

*/

function distanceBetween($fP1Lat, $fP1Lon, $fP2Lat, $fP2Lon){

$fEARTH_RADIUS = 6378137;

//角度换算成弧度

$fRadLon1 = deg2rad($fP1Lon);

$fRadLon2 = deg2rad($fP2Lon);

$fRadLat1 = deg2rad($fP1Lat);

$fRadLat2 = deg2rad($fP2Lat);

//计算经纬度的差值

$fD1 = abs($fRadLat1 - $fRadLat2);

$fD2 = abs($fRadLon1 - $fRadLon2);

//距离计算

$fP = pow(sin($fD1/2), 2)

cos($fRadLat1) * cos($fRadLat2) * pow(sin($fD2/2), 2);

return intval($fEARTH_RADIUS * 2 * asin(sqrt($fP)) 0.5);

}

/**

* 百度坐标系转换成标准GPS坐系

* @param float $lnglat 坐标(如:106.426, 29.553404)

* @return string 转换后的标准GPS值:

*/

function BD09LLtoWGS84($fLng, $fLat){ // 经度,纬度

$lnglat = explode(',', $lnglat);

list($x,$y) = $lnglat;

$Baidu_Server = "http://api.map.baidu.com/ag/coord/convert?from=0&to=4&x={$x}&y={$y}";

$result = @file_get_contents($Baidu_Server);

$json = json_decode($result);

if($json->error == 0){

$bx = base64_decode($json->x);

$by = base64_decode($json->y);

$GPS_x = 2 * $x - $bx;

$GPS_y = 2 * $y - $by;

return $GPS_x.','.$GPS_y;//经度,纬度

}else

return $lnglat;

}